Shape / columns · All operations
Find the time between two dates
A variant of Parse a date or time
Compute the interval or the count of units between two dates or times.
Status
- In arcform
Runs as a SQL step
arcform carries it as a
sql:step today.
The DuckDB step
Count the days, months and time between two dates
It reads the orders table the proofs share. Create it first:
CREATE TABLE orders AS SELECT * FROM (VALUES
(1, 'Alice Ng', 'north', DATE '2026-01-03', 120.00, 'widget', 'a|b', '{"channel":"web","items":[1,2]}'),
(2, 'alice ng', 'north', DATE '2026-01-05', 80.50, 'gadget', 'b', '{"channel":"shop","items":[3]}'),
(3, 'Bob Okafor', 'south', DATE '2026-01-05', 300.00, 'widget', 'a|c', '{"channel":"web","items":[4,5,6]}'),
(4, 'Carla Díaz', 'east', DATE '2026-01-09', NULL, 'gizmo', NULL, '{"channel":"web","items":[]}'),
(5, 'Bob Okafor', 'south', DATE '2026-01-12', 45.25, 'gadget', 'c', '{"channel":"phone","items":[7]}'),
(6, 'Dev Patel', 'west', DATE '2026-01-12', 510.00, 'widget', 'a', '{"channel":"web","items":[8,9]}'),
(7, 'Carla Diaz', 'east', DATE '2026-01-20', 99.99, 'gizmo', 'b|c', '{"channel":"shop","items":[10]}'),
(8, 'Dev Patel', 'west', DATE '2026-02-02', 510.00, 'widget', 'a', '{"channel":"web","items":[8,9]}'),
(9, 'Eve Larsen', NULL, DATE '2026-02-03', 15.00, 'gadget', NULL, '{"channel":"web","items":[11]}'),
(10, 'Alice Ng', 'north', DATE '2026-02-10', 220.00, 'gizmo', 'a|b|c', '{"channel":"phone","items":[12,13]}')
) t(order_id, customer, region, order_date, amount, product, tags, meta);Then run the statement:
CREATE TEMP TABLE result AS
SELECT order_id, order_date - DATE '2026-01-03' AS days_since_first FROM orders;
SELECT * FROM result;
CREATE TEMP TABLE units AS
SELECT date_diff('month', DATE '2026-01-31', DATE '2026-02-01') AS month_boundaries, date_sub('month', DATE '2026-01-31', DATE '2026-02-01') AS whole_months,
TIMESTAMP '2026-02-10 14:30:00' - TIMESTAMP '2026-02-10 12:00:00' AS elapsed;
SELECT * FROM units;
SELECT CASE WHEN ((SELECT days_since_first FROM result WHERE order_id = 10) = 38 AND (SELECT max(days_since_first) FROM result) = 38 AND (SELECT month_boundaries = 1 AND whole_months = 0 AND elapsed = INTERVAL 150 MINUTE FROM units)) THEN 'as expected' ELSE error('the gaps were not 38 days, one month boundary, no whole month and two and a half hours') END AS verdict;- It needs nothing installed beyond DuckDB itself.
- The statement checks its own result and raises an error when it is wrong: “the gaps were not 38 days, one month boundary, no whole month and two and a half hours”.
- It passed on DuckDB
v2.0.0 (Cyanoptera) d54cbbe3df.
What other tools call it
Meridian's classification; an independent blind rating agreed on 95.7% of 324 rows (variant, version 3).
Duckle (1)
Date Diffread 2026-09-25difference between two dates
Ibis (6)
DateDeltaread 2026-09-27Difference between two dates as a whole number of a chosen unit
DateDiffread 2026-09-27Difference between two dates, as an interval
TimeDeltaread 2026-09-27Difference between two times as a whole number of a chosen unit
TimeDiffread 2026-09-27Difference between two times, as an interval
TimestampDeltaread 2026-09-27Difference between two timestamps as a whole number of a chosen unit
TimestampDiffread 2026-09-27Difference between two timestamps, as an interval
KNIME Analytics Platform (1)
Date&Time Differenceread 2026-09-27Compute the difference between two date&time values
Polars (1)
business_day_countread 2026-09-27Count the business days between a start and an end date, end excluded
Background
In DuckDB, subtracting two TIMESTAMPs gives an INTERVAL describing their difference, while datediff counts the partition boundaries between them for a unit.[1] In DuckDB, subtracting one DATE from another returns the number of days between them as an integer rather than an interval.[1]
When to use it
In DuckDB, date_diff('month', DATE '1992-09-15', DATE '1992-11-14') counts month boundaries and returns 2, while date_sub, which counts whole months, returns 1 for the same dates.[2] Decide whether the question counts calendar periods crossed or whole periods elapsed before choosing the function: a person's age in whole years is the second kind. (Meridian's view)
In PostgreSQL, subtracting timestamptz '2013-03-01 12:00:00' from timestamptz '2013-07-01 12:00:00' can give 121 days 23:00:00, while age gives 4 mons.[3] PostgreSQL's age function uses the month of the earlier date when calculating partial months, so age('2004-06-01', '2004-04-30') yields 1 mon 1 day.[3] Choose between an elapsed difference and a calendar one deliberately whenever the two values lie either side of a clock change or a month end. (Meridian's view)
The method
In DuckDB, subtracting two TIMESTAMP values gives an INTERVAL with only days and microseconds components.[1] DuckDB's date_diff returns the signed number of part boundaries between two values, inclusive of the larger value and exclusive of the smaller.[4]
PostgreSQL's age performs field-by-field subtraction, giving a symbolic result that uses years and months rather than just days.[3] In PostgreSQL, converting each value to seconds with EXTRACT(EPOCH FROM ...) and subtracting gives the seconds between them, adjusting for month lengths, time zone changes and daylight saving time.[3]
Compared with the alternatives
DuckDB's date_sub truncates the interval between two values to whole multiples of the part, so for 1992-09-30 23:59:59 and 1992-10-01 01:58:00 it returns 1 hour where date_diff returns 2.[4]
Sources
- [1]Interval Type – DuckDBdocumentation
- [2]Date Functions – DuckDBdocumentation
- [3]PostgreSQL: Documentation: 18: 9.9. Date/Time Functions and Operatorsdocumentation
- [4]Timestamp Functions – DuckDBdocumentation